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98x-49=2^3-x^2
We move all terms to the left:
98x-49-(2^3-x^2)=0
We get rid of parentheses
x^2+98x-49-2^3=0
We add all the numbers together, and all the variables
x^2+98x-57=0
a = 1; b = 98; c = -57;
Δ = b2-4ac
Δ = 982-4·1·(-57)
Δ = 9832
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9832}=\sqrt{4*2458}=\sqrt{4}*\sqrt{2458}=2\sqrt{2458}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(98)-2\sqrt{2458}}{2*1}=\frac{-98-2\sqrt{2458}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(98)+2\sqrt{2458}}{2*1}=\frac{-98+2\sqrt{2458}}{2} $
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